Truncated match.
PICList
Thread
'Power Mosfet'
1998\08\25@204101
by
Ryan Pogge
Ok I just went through my workbench and found this power mosfet from radio
shack.....
its a IFR510
N-channel 60 volt
here is my question: are you ready:????
what the heck is this thing for?
hehe dont yell at me please :) I realy dont know what its for.... is it some
type of electronic switch?
I have never used a Mosfet of any kind before,.... I havent used much of
anything to tell you the truth.
what would it be usefull for?
sorry for the dumb question... just bored I guess....
regards,
Ryan
1998\08\25@213526
by
russellh
Ryan Pogge wrote:
>
> Ok I just went through my workbench and found this power mosfet from radio
> shack.....
> its a IFR510
> N-channel 60 volt
>
> here is my question: are you ready:????
>
> what the heck is this thing for?
<snip>
An IRF510 is a switch. The gate is the control, you charge it up (like a
capacitor) to about +10 volts compared to the source, and the switch is
on. On, it's resistance is about .6 Ohms. The source must be more
negative than the drain, as the mosfet simply conducts, switched on or
not, when hooked up the other way.
Discharge the gate (short it to the source) to switch it off again.
Thare's more, but you don't sound too terribly interested anyway, so I
won't bother you with it. You can try experimenting with it, and learn
more that way.
International Rectifier also sell some MOSFET's that are fully on at 5
volts. Hmmmmm.
Russell Hedges
1998\08\25@234417
by
Sean Breheny
Hi all,
At 06:29 PM 8/25/98 -0700, you wrote:
>on. On, it's resistance is about .6 Ohms. The source must be more
>negative than the drain, as the mosfet simply conducts, switched on or
>not, when hooked up the other way.
I might be wrong, but I don't think that this is exactly correct. AFAIK,
all fets are pretty symetrical when it comes to the source and drain. So,
as long as you charge the gate more positive than EITHER drain or source by
the VgsON threshold, it will turn on, and it doesn't matter which is more
positive, drain or source. Usually, the actual source is kept more negative
because the manufacturer optimizes the gate-source characteristics more
than gate-drain characteristics (i.e., gate-source capacitance is kept
lower in smal signal fets, I don't know if the same is true in power mosfets).
Sean
+--------------------------------+
| Sean Breheny |
| Amateur Radio Callsign: KA3YXM |
| Electrical Engineering Student |
+--------------------------------+
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1998\08\26@002545
by
James Cameron
Ryan Pogge wrote:
> its a IFR510
> what the heck is this thing for?
Russell gave a good answer, Ryan, but I'll add a bit from my perspective
... I've only just learned about these things in the past few months.
They are sort of like a transistor, in that they switch current on and
off, but they are most often used for solid on-off, sort of like how a
relay works, rather than partial on-off like a transistor.
How useful is it to you? Think of any case where you want to use a
relay to switch DC, and try out the MOSFET in it's place. Quieter, more
reliable, no moving parts, and much easier to destroy.
--
James Cameron (.....james.cameronKILLspam
@spam@digital.com)
Digital Equipment Corporation (Australia) Pty. Ltd. A.C.N. 000 446 800
1998\08\26@010738
by
russellh
Sean Breheny wrote:
>
> Hi all,
>
> At 06:29 PM 8/25/98 -0700, you wrote:
> >on. On, it's resistance is about .6 Ohms. The source must be more
> >negative than the drain, as the mosfet simply conducts, switched on or
> >not, when hooked up the other way.
>
> I might be wrong, but I don't think that this is exactly correct. AFAIK,
> all fets are pretty symetrical when it comes to the source and drain.
These MOSFET's have an inhearent reverse diode in them, so that they
conduct when connected in reverse. As far as I know, all the big ones
do. Sometimes the schematic symbol shows this diode, sometimes not.
Keep in mind, though, that a MOSFET when on is a resistance, and not a
junction drop. In this case, the on resistence is .6 OHMS, a number not
at all related to a .6 VOLT junction drop.
Russell Hedges
1998\08\26@011530
by
russellh
James Cameron wrote:
>
> Ryan Pogge wrote:
> > its a IFR510
> > what the heck is this thing for?
>
> Russell gave a good answer, Ryan, but I'll add a bit from my perspective
> ... I've only just learned about these things in the past few months.
Aww shucks! Your turning my head.
<snip>
> How useful is it to you? Think of any case where you want to use a
> relay to switch DC, and try out the MOSFET in it's place. Quieter, more
> reliable, no moving parts, and much easier to destroy.
>
Not to mention, they take almost no drive at all. I have sorted batches
of hundreds of MOSFET's by gate capacitance, big 14 Amp 400 Volt things,
and
the most gate capacitance I saw was about 35 pF. That's thirty five pico
Farads.
And they are usually cheaper than a relay.
Russell Hedges
1998\08\26@013159
by
Mike Keitz
|
On Tue, 25 Aug 1998 22:03:00 -0400 Sean Breheny <shb7
KILLspamCORNELL.EDU>
writes:
>Hi all,
>
>At 06:29 PM 8/25/98 -0700, you wrote:
>>on. On, it's resistance is about .6 Ohms. The source must be more
>>negative than the drain, as the mosfet simply conducts, switched on
>or
>>not, when hooked up the other way.
>
>I might be wrong, but I don't think that this is exactly correct.
>AFAIK,
>all fets are pretty symetrical when it comes to the source and drain.
Power MOSFETs have a diode inherent in their structure so they will
conduct if the drain is reverse-biased from the source. The gate-source
voltage determines the amount of conduction, the gate-drain voltage has
rather little effect. They are made with the gate and source close to
each other on the top of the chip; the drain is the substrate of the
chip.
Should you need to operate the drain negative with respect to the source,
P-channel power MOSFETs are made. But, there are optocouplers with a FET
output that will switch signals of either polarity. Apparently the FET
in these is more symmetrical, or at least it doesn't have the diode. I
haven't seen just the FET part offered as a discrete device.
>optimizes the gate-source characteristics
>more
>than gate-drain characteristics (i.e., gate-source capacitance is kept
>lower in smal signal fets, I don't know if the same is true in power
>mosfets).
In a power FET, the gate-source capacitance is much more than the
gate-drain capacitance, but the latter usually is more of a problem in
switching circuits due to the Miller effect.
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1998\08\26@023807
by
Bob Blick
Hi Sean,
You are thinking JFETs, not MOSFETs.
-Bob
At 10:03 PM 8/25/98 -0400, you wrote:
>I might be wrong, but I don't think that this is exactly correct. AFAIK,
>all fets are pretty symetrical when it comes to the source and drain. So,
>as long as you charge the gate more positive than EITHER drain or source by
>the VgsON threshold, it will turn on, and it doesn't matter which is more
>positive, drain or source. Usually, the actual source is kept more negative
>because the manufacturer optimizes the gate-source characteristics more
>than gate-drain characteristics (i.e., gate-source capacitance is kept
>lower in smal signal fets, I don't know if the same is true in power
mosfets).
>
>Sean
1998\08\26@053533
by
Ron Fial
... But, there are optocouplers with a FET
>output that will switch signals of either polarity. Apparently the FET
>in these is more symmetrical, or at least it doesn't have the diode. I
>haven't seen just the FET part offered as a discrete device.
Actually, these optocouplers generally have an N Power Fet and a P Power FET in
series. Each has an intrinsic source/drain diode, but since they are pointing o
pposite directions, no current can flow unless you turn on one or both of the F
ETs.
These devices are also made with IGBTs, in which case the intrinsic diodes are n
ot present, they can handle much more current, but on/off time is slower.
Ron Fial
1998\08\26@073305
by
Walter Markiw
|
Hi all,
I've been toying arround with power mosfets for some time now,hanling
some high
voltage switching (300 volts,maybe 1 or two amps).N-channel mosfets require
at least
gate voltage to be 10-12 volts above source to get in full conduction,which
means that
if your high voltage rail is 300 volts,and you have two mosfets in a half bridge
configuration,the upper mosfet will require 300 + 12 = 312 volts for turning
on.There
are drivers from IR to achieve this,but I'd like to do it without them.
The approach is usually making the source voltage float to the source
level,
using a bootstrap diode and cappacitor to provide the overvoltage when the
fet is to be
turned on.This has the inherent limitation of not being able to keep the
mosfet in conduction for a period longer than the charge of the cappacitor
allows it to.Then,
the lower mosfet must put the upper one's source to ground to allow the
cappacitor
to recharge from a 15 volt power source through the bootstrap diode.
Please excuse the roughness of the exposition,but this is mainly the
result of months of burning things on the protoboard with very little
theoretical background.
Can any of you show me how you would build the circuit to drive the
upper side mosfet,with the bootstrap diode and cappacitor?
1998\08\26@075215
by
Ryan Pogge
|
ahhhh
cool man... so this thing is good for driveing DC motors and such...?????
someone said somtin about an audio amp too.... so it would be just like a
transistor based audio amp?
I might try that. But what is the advantage of useing this for an audio amp
versus a transistor. just more watts????
{Quote hidden}>Ryan Pogge wrote:
>> its a IFR510
>> what the heck is this thing for?
>
>Russell gave a good answer, Ryan, but I'll add a bit from my perspective
>... I've only just learned about these things in the past few months.
>
>They are sort of like a transistor, in that they switch current on and
>off, but they are most often used for solid on-off, sort of like how a
>relay works, rather than partial on-off like a transistor.
>
>How useful is it to you? Think of any case where you want to use a
>relay to switch DC, and try out the MOSFET in it's place. Quieter, more
>reliable, no moving parts, and much easier to destroy.
>
>--
>James Cameron (
.....james.cameronKILLspam
.....digital.com)
>Digital Equipment Corporation (Australia) Pty. Ltd. A.C.N. 000 446 800
>
1998\08\26@082511
by
Jim Manzari
Regarding the comments on MOSFETs...Can anyone tell me if there is a
MOSFET that can control say 100 Amps? I would like to replace a
mechanical battery switch with a MOSFET one. For this I would like a
minimum of on-resistance, say less than 0.1 ohms if possible. Of
course, I realize that careful attention will have to be paid to the
thermal design aspect. Does any such device exist? If so, please
point me to its data sheet.
TIA
Jim Manzari
1998\08\26@082729
by
Sean Breheny
Hi all,
Thanks for the correction. I guess I should read the WHOLE section on FETs
in "The ART of Electronics" before engaging my mouth on this subject.
Seriously, though, for my own edification, if I took a MOSFET that lacked a
protection diode, wouldn't it be able to work backwards, albeit with
different characteristics?
Thanks,
Sean
At 11:35 PM 8/25/98 -0700, you wrote:
{Quote hidden}>Hi Sean,
>
>You are thinking JFETs, not MOSFETs.
>
>-Bob
>
>At 10:03 PM 8/25/98 -0400, you wrote:
>>I might be wrong, but I don't think that this is exactly correct. AFAIK,
>>all fets are pretty symetrical when it comes to the source and drain. So,
>>as long as you charge the gate more positive than EITHER drain or source by
>>the VgsON threshold, it will turn on, and it doesn't matter which is more
>>positive, drain or source. Usually, the actual source is kept more negative
>>because the manufacturer optimizes the gate-source characteristics more
>>than gate-drain characteristics (i.e., gate-source capacitance is kept
>>lower in smal signal fets, I don't know if the same is true in power
>mosfets).
>>
>>Sean
>
+--------------------------------+
| Sean Breheny |
| Amateur Radio Callsign: KA3YXM |
| Electrical Engineering Student |
+--------------------------------+
Save lives, please look at
http://www.all.org
Personal page: http://www.people.cornell.edu/pages/shb7
EraseMEshb7spam_OUT
TakeThisOuTcornell.edu
Phone(USA): (607) 253-0315
1998\08\26@084836
by
Thomas Magin
At 13:31 26.08.98 +0200, you wrote:
>Regarding the comments on MOSFETs...Can anyone tell me if there is a
>MOSFET that can control say 100 Amps? I would like to replace a
Hi,
instead of using MOSFETs, have a look at SCRs or IGBTs.
Thomas
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1998\08\26@085228
by
Montaigne, Mike
|
(given you don't want to use a chip designed for this purpose)
How about an isolated power supply and a optical coupler.
Mike
{Quote hidden}> ----------
> From: Walter Markiw[SMTP:
@spam@markiwKILLspam
OVERNET.COM.AR]
> Sent: Wednesday, August 26, 1998 7:40 AM
> To:
KILLspamPICLISTKILLspam
MITVMA.MIT.EDU
> Subject: Re: Power Mosfet
>
> Hi all,
> I've been toying arround with power mosfets for some time
> now,hanling
> some high
> voltage switching (300 volts,maybe 1 or two amps).N-channel mosfets
> require
> at least
> gate voltage to be 10-12 volts above source to get in full
> conduction,which
> means that
> if your high voltage rail is 300 volts,and you have two mosfets in a half
> bridge
> configuration,the upper mosfet will require 300 + 12 = 312 volts for
> turning
> on.There
> are drivers from IR to achieve this,but I'd like to do it without them.
> The approach is usually making the source voltage float to the
> source
> level,
> using a bootstrap diode and cappacitor to provide the overvoltage when the
> fet is to be
> turned on.This has the inherent limitation of not being able to keep the
> mosfet in conduction for a period longer than the charge of the cappacitor
> allows it to.Then,
> the lower mosfet must put the upper one's source to ground to allow the
> cappacitor
> to recharge from a 15 volt power source through the bootstrap diode.
> Please excuse the roughness of the exposition,but this is mainly
> the
> result of months of burning things on the protoboard with very little
> theoretical background.
> Can any of you show me how you would build the circuit to drive the
> upper side mosfet,with the bootstrap diode and cappacitor?
>
1998\08\26@091710
by
|
> Regarding the comments on MOSFETs...Can anyone tell me if there is a
> MOSFET that can control say 100 Amps? I would like to replace a
> mechanical battery switch with a MOSFET one. For this I would like a
> minimum of on-resistance, say less than 0.1 ohms if possible. Of
> course, I realize that careful attention will have to be paid to the
> thermal design aspect. Does any such device exist? If so, please
> point me to its data sheet.
>
> TIA
>
> Jim Manzari
>
I think you'd want *much* less than 0.1 ohms
P=I^2R =100*100*0.1 = 1000 Watts!!!!
Thats a lot of heat to get rid of. Would this be 100 Amps continuous or
pulsed? If the average current is lower, there are many devices readily
available that can take 25 Amps or more peak current. Bearing in mind that
the gate takes no current (unless changing state) you could by a load of
these and parallel them up. This is the approach taken by the PWM motor
controllers used for Radio controlled models.
Mike Rigby-Jones
RemoveMEmrjonesTakeThisOuT
nortel.co.uk
1998\08\26@093713
by
Chip Weller
|
Jim Manzari wrote:
>Regarding the comments on MOSFETs...Can anyone tell me if there is a
>MOSFET that can control say 100 Amps? I would like to replace a
>mechanical battery switch with a MOSFET one. For this I would like a
>minimum of on-resistance, say less than 0.1 ohms if possible. Of
>course, I realize that careful attention will have to be paid to the
>thermal design aspect. Does any such device exist? If so, please
>point me to its data sheet.
>
>TIA
>
>Jim Manzari
Yes, although I do not have any references near by. These typically are
modules which mount several MOSFET die onto a metal back plate and then
provide a sealed package. I have typically just use several parallel
MOSFETs separately strapped to a heat sink. When doing this use separate
gate drive resistors and do not attempt to use the parallel combination
in a linear mode -- it will fail at a much lower than expected current
as current is not shared well unless the parts are fully on.
One project I did had an H-bridge which switch currents on the order of
400Amps at 24VDC at around 24KHz PWM. BTW it is very easy to release the
factory installed smoke from these devices. Make sure the heat sink is
adequate and make sure that the source to drain voltage does not get
exceeded when you open the circuit. Typically this requires good bypass
on the power supply and possibly external catch diodes (the parasitic
MOSFET reverse diodes do fairly well in most cases) and typically double
the source to drain voltage over the voltage you are switching.
Chip Weller
1998\08\26@101109
by
Pavel Korensky
|
At 20:41 25.8.1998 -0400, you wrote:
>Ok I just went through my workbench and found this power mosfet from radio
>shack.....
>its a IFR510
>N-channel 60 volt
>
>here is my question: are you ready:????
>
>what the heck is this thing for?
>hehe dont yell at me please :) I realy dont know what its for.... is it some
>type of electronic switch?
:-) If you will find one more IRF510 and two more IRF9510 (P channel
MOSFETS), you can build a nice H-bridge and drive motor with your PICs.
Seriously, power MOSFETS are like switches, but you need to solve some
specific problems when you want to use them. The whole problematic is
probably a bit long for e-mail answer, but you can find very good
explanation of these components in "Art of Electronic" or similar book.
Also, International Rectifier (company which manufacture IRF510 and
hundreds of other similar MOSFETS) have some PDF sheets about MOSFETS on
their web page.
PavelK
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1998\08\26@125120
by
Jim Manzari
Rigby-Jones, Michael [PAI01:4837:EXCH] wrote:
>
> I think you'd want *much* less than 0.1 ohms
>
> P=I^2R =100*100*0.1 = 1000 Watts!!!!
>
> Thats a lot of heat to get rid of. Would this be 100 Amps continuous or
Michael,
How right you are! I meant to say 0.01 ohms. Now that people have
directed me to some data sheets I see that 0.008 ohms is possible.
Still a good deal of heat at 100A, but at least manageable. In actual
practice I would expect continuous current to be less than 100A since
the batteries can not be charged at greater than about C/10 to C/20.
Thanks for pointing out my mistake.
Regards,
Jim Manzari
1998\08\26@125331
by
wwl
|
On Wed, 26 Aug 1998 13:31:05 +0200, you wrote:
>Regarding the comments on MOSFETs...Can anyone tell me if there is a
>MOSFET that can control say 100 Amps? I would like to replace a
>mechanical battery switch with a MOSFET one. For this I would like a
>minimum of on-resistance, say less than 0.1 ohms if possible. Of
>course, I realize that careful attention will have to be paid to the
>thermal design aspect. Does any such device exist? If so, please
>point me to its data sheet.
>
>TIA
>
>Jim Manzari
MOSFETs can be paralleled quite easily, so a few smaller ( much
cheaper) devices could easily do it. You can get To-220 devices rated
at over 50A, although in practice packaging and connection issues mean
you wouldn't be able to get this performance in practice.
Many of the big MOSFET makers (IR, MOT, ST, Semikron) do large module
type devices with screw-terminal connections, with ratings to 200A but
they are expensive.
e.g. ST STE25N06, 250A, 60V, 0.004R Ron, UKP37 (US$60) 1-off
you can get a lot of TO-220 or TO-3P devices for that money!
____ ____
_/ L_/ Mike Harrison / White Wing Logic / spamBeGonewwlspamBeGone
netcomuk.co.uk _/ L_/
_/ W_/ Hardware & Software design / PCB Design / Consultancy _/ W_/
/_W_/ Industrial / Computer Peripherals / Hazardous Area /_W_/
1998\08\26@133558
by
Mike Keitz
|
On Wed, 26 Aug 1998 13:31:05 +0200 Jim Manzari <TakeThisOuTmanzariEraseME
spam_OUTBLUEWIN.CH>
writes:
>Regarding the comments on MOSFETs...Can anyone tell me if there is a
>MOSFET that can control say 100 Amps? I would like to replace a
>mechanical battery switch with a MOSFET one. For this I would like a
>minimum of on-resistance, say less than 0.1 ohms if possible.
You need a much lower on-resistance than that. At 0.1 ohms, the FET
would drop 10 V and dissipate 1000 W.
There may not be a simgle FET with the ratings you need, but they are
easy to combine in parallel. Five IRFZ40's at 0.018 ohms each may be
enough, the combination would drop 0.36 V and dissipate 36 W (7.2 W per
FET).
A FET switch is not exactly the same as a relay since it will conduct
through the diodes in the opposite direction.
_____________________________________________________________________
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1998\08\27@041820
by
Thomas Magin
At 17:27 26.08.98 +0200, you wrote:
>Rigby-Jones, Michael [PAI01:4837:EXCH] wrote:
>>
>> I think you'd want *much* less than 0.1 ohms
>>
>> P=I^2R =100*100*0.1 = 1000 Watts!!!!
>>
>> Thats a lot of heat to get rid of. Would this be 100 Amps continuous or
>
>Michael,
>
>How right you are! I meant to say 0.01 ohms. Now that people have
>directed me to some data sheets I see that 0.008 ohms is possible.
Hi,
IRF: IRFP064N, 98A DC, 390A pulsed, 0.008R
Toshiba: 2SK2987, 70A DC, 280A pulsed, 0.004R (!)
So long
Thomas
=8-)
--
**********************************************************
* Thomas Magin FON: ++49-761-4543-489 *
* marquette-Hellige GmbH FAX: -507 *
* E-FW / Emergency Systems email: RemoveMEmagin
TakeThisOuThellige.de *
* Munzinger Str. 3 *
* D-79111 Freiburg / Germany *
**********************************************************
1998\08\27@073916
by
Russell McMahon
|
If you want to use the sort of circuit you have just described to
provide high side drive you MUST occasionally effectively take the
hi-side FETS gate drive power supply capacitor down to ground so that
it can be charged (as you described). There are other schemes such as
using a transformer and an oscillator to provide the high side drive
or providing the drive directly via a pulse transformer. All of these
incorporate an element of black magic. The very large and rather
rapid voltage swings as the upper FET/IGBT switches tends to produce
large dv/dt' in your driver circuit which can lead to false and/or no
triggering etc. Stray capacitance (and any other stray effects you
can possibly think may exist :-)) need to be accounted for. Try doing
a web search for terms such as "hi side drive*" or "h bridge". There
are many ICs available and if you are only building one off's it is
probably much easier to use one. A major advantage of typical hi-side
drivers is the provision of 'shoot through" protection (prevents both
FETs being on at once, lock out if the hi-side power supply cap's
voltage drops too low and lockout if the bottom driver supply voltage
is too low. There is also often over-current sensing and possibly
other protection. Doing all this yourself is possible but distracts
you from the main application.
If you want to build an oscillator type high side power supply the
ubiquitous 555 timer is generally adequate to the task driving a
small toroid with suitable turns. remember that the toroid needs to
provide high side voltage isolation - an insulated core is advisable
if you are using hundreds of volts.
I haven't used a 555 for this specific application but there have
been functionally identical units in hobby mags - some other
PIC-listers may be able to provide actual values.
{Original Message removed}
1998\08\27@124858
by
Mercy
|
...
>or providing the drive directly via a pulse transformer. All of these
>incorporate an element of black magic. The very large and rather
>rapid voltage swings as the upper FET/IGBT switches tends to produce
>large dv/dt' in your driver circuit which can lead to false and/or no
>triggering etc. Stray capacitance (and any other stray effects you
>can possibly think may exist :-)) need to be accounted for. Try doing
>a web search for terms such as "hi side drive*" or "h bridge".
...
There is no black magic in using pulse transformer. We have one of the HP
switched power supply in our lab and the drive in done on a half-bridge
using separate pulse transformers. The design is very simple, and works
perfectly ( pulse transformer + resistor + zener diode not to fry the gate )
I you are interested, please tell me, but only if it is for personnal
design ( HP would kill me/us else :-)
------------------------------------------------------
N'oubliez jamais que nous voyons plus facilement la /
paille dans l'oeil du voisin que la poutre dans le /
notre. /
--------------- /
MERCY Jean-marc Maitre de conference /
University Montpellier 2 /
Sciences et techniques du languedoc /
Place Eugene Bataillon /
34095 Montpellier cedex 5 /
FRANCE /
Tel : 33-4-67-14-48-20 /
Fax : 33-4-67-14-37-60 /
Email : mercyEraseME
.....ges.univ-montp2.fr /
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